Hi Folks
I have been following this thread for a while, enjoying the guesses.
But since we are encouraged to guess, even by some our esteemed moderators, I'll participate as well ;-)
I'll send this wild guess over the pond just for the fun of it.
So here is my reasoning:
The solution looks quite saturated, which are supposed to be 6.8g/ml * 1100ml appr 750g (ish)
AuCl
3 divided by saturation grade, lets say 3/4 saturated, which gives 562,5 g AuCl
3
This will in turn give 562.5/303.325 = 1.85*197 = 365.3 grams, then subtract the X factor,
and voila my guess arrives at
336.6g give or take a bit :-D
At the end of the day, my guess is waay out there or the only one close so far ;-)
Have a fantastic day all :mrgreen: