Tin Monster rears its ugly head.

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glondor

Well-known member
Joined
Jun 13, 2010
Messages
1,539
Hey all. Looking for some advise. Processing 15 pounds of pins. Nice looking material. The issue.... They have reduced to a massive amount of metastanic acid/ gold foil goodness. I cleaned out as much of the foils as I could using a screening method. >>>>>
DSCN3170.jpg


I am left with this.>>>>>
DSCN3173.jpg


I will have the mass dried in a few hours, and will put the heat to it then. (incinerate)

My question.... Does any one have a better/faster way? There is at least 4 pounds in the dish....

Cheers and thanks for your help Mike.
 
when that happens to me, i incinerate and boil the solids in hcl. the copper will oxidize and be removed and the tin will dissolve too. it will leave some off white colored powder that is non-soluble in hcl and gold foils.
 
Hey Geo. Thanks. Yes that is the plan. I wonder, do you know how much hcl for 5 pounds of this goo?
 
unsure. incinerating will reduce the weight to a few ounces though. right now most of the weight is liquid. i would think between 500 to 1000 ml's.
 
Can you tell us more Lino. After a long hard boil in HCL there is still a lot of crumble left. And as usual, the hcl wash is positive for gold. Putting the crumble in A/R now. (after a wash)
 
Have you tried sulphuric? According to Hoke (P70/71) the tin paste will dissolve in dilute or concentrated sulphuric.
 
Incineration is a very good method to use.


If I had a large amount of these salts, I may choose another option.
One different method I may have tried to deal with this large batch of salts, would be to take the blue copper and tin salts with gold foils, add them into a distilling rig, add a dilute sulfuric acid (about 50% H2SO4), distilling off nitric acid, capture the condensed nitric acid which formed, this would leave a copper and tin sulfates with gold foils, in which the tin sulfate and copper sulfate could be dissolved away from the gold foils with boiling hot water.

The tin sulfate SnSO4 has a solubility of 33 grams in 100ml water @ 25 degrees C.

The copper sulfate is easier to dissolve in boiling water if done before hard crystals form, copper sulfate solubility in water, 310g/L @ 0 deg C, and 2033g/L @ 100 deg C.


Tin in this mix may reduce some of the copper salts to copper oxide or copper (if very large amounts of tin were involved), this small amount of copper or copper salts (if they did happen to be formed) could be dissolved away from gold foils, before processing the gold.
 
Amazing. Thanks guys. So there is a conversion we can all do that will make a water soluble tin. So butcher, you say, (after incineration) just add sulfuric and distill and it will make nitric and make the tin wash away in boiling water. That is fantastic.

Does anything have to be added with the sulfuric to make it distill nitric acid? I have never tried to make Nitric and am not at all familiar with the chemistry.

If that is all there is to it........ Many of us will be slapping our fore heads. I read dozens and dozens of posts on this last night and it seemed everyone is left hanging unsolved. Thanks so much Butcher, you may have the answer to the biggest pain in escrap recycling.
 
of course, i didnt ask if you digested the base metal with nitric acid or AP. i was assuming AP for some insane reason. i do understand what it means when i assume.

sorry about that
 
glondor,

Incineration would drive off the NOx gas from the tin meta-stannic salts SnO3, and copper nitrate salts
Incinerating the Cu(NO3)2 would form copper and tin oxides with your gold flakes, as the NOx gas was drive off by the heat, notice we drove off the previous acid of these salts, the gas from incineration could be captured and bubbled into water to form some nitric acid, but with incineration this is a bit difficult to do.

Also notice after incineration we no longer have nitrates, so we could not take the copper and tin oxides and make nitric now, at least not easily or we would not want too at this point after incineration.

So continue with the process your using now to dissolve the tin and copper oxides from your gold with HCl boil and washes.

What I was saying was instead of incineration; I may have used the copper nitrate salts (with meta-stannic salts, and gold foils) to make nitric, and tin sulfate and copper sulfate.

Copper nitrate distilled with sulfuric acid, gives nitric acid and copper sulfate.

Cu(NO3)2 + H2SO4 --> 2HNO3 + CuSO4

Tin nitrate would react in a similar manner.

Both tin sulfate and copper sulfate are water-soluble; the gold is not soluble as a sulfate.

The reaction would need to be distilled until the nitric acid has been distilled off, the solution would change from a green color to a blue color when all of the nitric was distilled off, the blue thick liquid solution would be copper sulfate, tin sulfate, and your gold foils, when reaction was completed distilling the nitric you would need to add boiling water to the blue solution before letting it cool, (we do not want it to cool and form crystals that would take more water or be harder to re-dissolve) once this copper sulfate solution was diluted with boiling water, to keep copper and tin soluble we can let it sit, and our gold would settle to the bottom of the vessel, and then we could decant the tin and copper sulfate solution from our gold.

Reading this process I use to make nitric acid while removing gold plating from copper pins, may help in understanding this more:

http://www.google.com/search?hl=en&as_q=killing+two+birds+one+rock+&num=1000&ft=i&as_sitesearch=goldrefiningforum.com&as_qdr=all&as_occt=any


I also assumed this was copper nirates with tin from a nitrate solution because I believe you mentioned Meta stannic acid (which would be a salt of tin and nitric acid).
 
butcher said:
What I was saying was instead of incineration; I may have used the copper nitrate salts (with meta-stannic salts, and gold foils) to make nitric, and tin sulfate and copper sulfate.

Copper nitrate distilled with sulfuric acid, gives nitric acid and copper sulfate.

Cu(NO3)2 + H2SO4 --> 2HNO3 + CuSO4

Tin nitrate would react in a similar manner.

.... snip ....

I also assumed this was copper nirates with tin from a nitrate solution because I believe you mentioned Meta stannic acid (which would be a salt of tin and nitric acid).
I started to write that "There isn't any tin nitrate, tin reacts with HNO3 to form metastannic acid, H2SnO3, a white substance insoluble in alkalies or acids." but then researching the subject further I found that according to Analytical Chemistry Tin
Tin in strong nitric acid isn't dissolved, it is oxidized into our metastannic acid.
3Sn + 4HNO3 + H2O = 3 H2SnO3 + 4NO
But in weak nitric acid it dissolves tin into tin nitrate. How weak, I don't know, haven't tried it but now when I read about it I would like to try. 8)

Reading further I see that tin nitrate and sulfate is unstable and breaks down into acid and stannic hydroxide.

So when trying to distill nitric acid from nitrates with metastannic acid it is only the copper and zinc nitrates that forms nitric acid. It would be better to decant / filter off the nitrates from the solids and create your nitric acid from that. Then treat the solids separately.

On the bottom of page 274 in the document above it is mentioned that
Analytical Chemistry said:
If the beta-stannic [metastannic] acid is treated for a long time with concentrated hydrochloric acid, the Sn5O5 group is finally broken down, and the tin goes into solution in the form of ordinary alpha-stannic chloride
That sounds like the metastannic acid could be dissolved with hydrochloric acid... but if we comes from a nitric solution we would form aqua regia and dissolve our gold. If we incinerate to get rid of the nitrate we turn the metastannic acid into tin oxide which is another story for another day.

It is obvious that I won't solve the tin problem today... :mrgreen:

Göran
 
i thought that by calcining the tin oxide, it would drive off one of the oxygen atoms. i was told it was more complicated than that. until i better understand the chemistry all i can go by is cause and effect. if you heat tin oxide whether it comes from decomposed tin chloride or nitric acid to a glowing hot state, the tin will dissolve in hot hcl acid. that amount of tin oxide (metastannic acid) could only have come from bronze pins. i doubt there was that much solder in the mix. i get it when im dissolving alot of computer pins in AP given the amount of oxygen i put in solution. thats the way i deal with it.incinerate and remove what will dissolve with hot hcl and whats left is more easily dealt with.
 
g_axelsson,
Quote:
"So when trying to distill nitric acid from nitrates with metastannic acid it is only the copper and zinc nitrates that forms nitric acid. It would be better to decant / filter off the nitrates from the solids and create your nitric acid from that. Then treat the solids separately."


The salts in discussion were concentrated and almost dried so they would contain nitrate salts of copper (zinc) and tin all of which would form HNO3 in the reaction of distilling with sulfuric acid, and be converted to sulfates in the reaction.

The tin in solution as mettastannic acid H2SnO3 really does not dissolve, if captured in a filter as gelatin or dried to salts (with the copper salts), would be a salt of nitric acid and tin, thus a tin nitrate salt, although I am unsure how acidic the tin salts would remain with the copper (zinc) salts, the tin is still a salt of nitric acid thus a tin nitrate salt.

The soluble copper nitrate solution when dried or almost dry to crystallized salts also is a salt of nitrates as well as any zinc if these salts came from brass instead of just copper scrap.

Adding these nitrate salts (I presume Mainly copper nitrate due to proportion of metals dissolved to from these salts), to a distilling rig, adding dilute sulfuric acid, and distilling.

The sulfuric acid will begin reacting with these nitrate salts, dissolving them into solution, and NOx gas would begin to evolve, beginning to convert them into copper and tin sulfate, but also the hydrogen from the sulfuric acid would also again form nitric acid in this solution.

So at the beginning we would have a solution of copper sulfate and copper nitrate, mixed with tin sulfate and metastannic acid, (and zinc if involved) some NOx gases evolving but most of this gas would just stay in the dilute solution.

At first in the dilute solution of sulfuric acid most of these gases would not leave solution to much extent, but with heat these would begin to evolve, at first mostly water vapors with very little acidic fumes or NOx fumes, but as the distilling of the solution proceeded the nitric vapors would be more concentrated, until the 68% HNO3 was distilling off with the NOx gas, the copper and tin nitrates would further be convert to copper and tin sulfates in solution as the nitric acid was removed from the system by distilling it off, eventually you would be left with no nitric or nitrates in the distilling rig only copper (zinc if these salts came from brass) and tin sulfates dissolved in solution left in the boiling vessel with your gold.

(Nitric acid will distill off leaving only a soluble metal sulfate solution, and the insoluble undissolved gold).

The metals do not leave as gas in the fumes, from the distilling rig, and neither will the sulfuric acid (too high of a boiling point).

Another action of the reaction is as we are distilling, as the nitric leaves solution and the sulfuric acid in the boiling reactor concentrates the sulfuric acid, taking over the metals in solution, the tin is no longer metastannic acid but converts to tin sulfate, the copper converts to copper sulfate, and the gold is freed to settle in this solution of water soluble metal sulfates.

Once the reaction is complete the vessel opened and this solution is diluted with boiling water, the reason for the boiling water is because this should be done while the concentrated copper sulfate solution is still hot, this keeps from breaking the glass with thermal shock, and dilutes the thick copper sulfate syrup while still hot so the crystals will not form before solution is cooled and thus easier to be diluted.

The gold in this copper and tin sulfate solution can now be left to cool, the gold will settle to the bottom of the vessel, and then we can decant the sulfate solution from our gold.

(This method will also work for other salts or very concentrated solutions, as an alternative. or a pre-step to break the colloids, dissolve (or convert) the tin and copper or other metals, the hot concentrated sulfuric acid can also break the colloids of the gold if any chlorides were involved or if we had a solution of HCL or copper chloride salts and colloidal gold mixed with gold flakes, the HCl can be distilled off, the concentrated sulfuric breaking the gold colloids, tin in solution converted to soluble tin sulfate, and copper chloride converted to copper sulfate, and the gold freed to settle in the solution of soluble copper, tin or other metal sulfates).

The gold separated by this method can then be incinerated (without the large volume of other metal salts) before treating further.

This distilling method would be best with large batches of metal salts, or large batches of concentrated solutions, where filtering or separating gold from the large volume of salts or solutions would be troublesome, or it would be troublesome to incinerate this large volume of salts, because of the large volume of gases that would form from the volume of salts, and the volumes of toxic gases formed by the incineration of these metal salts.
 
Hi Butcher, I agree with most of what you are saying but this is what I'm reacting on.
butcher said:
The tin in solution as metastannic acid H2SnO3 really does not dissolve, if captured in a filter as gelatin or dried to salts (with the copper salts), would be a salt of nitric acid and tin, thus a tin nitrate salt, although I am unsure how acidic the tin salts would remain with the copper (zinc) salts, the tin is still a salt of nitric acid thus a tin nitrate salt.

This is where I think you make a mistake. Just because the metastannic acid is created by nitric and tin doesn't mean it is a salt of nitric acid.
A salt of nitric acid contains the nitrate ion NO3- but the metastannic acid is H2SnO3 and contains no NO3- ion. You can't create the ion by adding sulfuric acid, the only nitrates in the mix is the ions coming from the copper (and zinc) nitrate.
Just as auric chloride isn't a salt of nitric acid even though you can create it by aqua regia and gold the nitric acid reaction with tin is an oxidation of the tin.

Just think of what would happen when the copper (and zinc) nitrate is filtered off, could you still distill nitric acid off the metastannic acid and sulphuric acid?

I'm already late for work so I have to dig deeper into this discussion later tonight. Tin chemistry isn't easy, it has a lot of different faces and is even compared to the silicates as it has a lot in common with how SiO2 work in mineralogy.

Hey, this is fun, discussing and arguing with you. I hope you feel that too. 8)

Göran
 
Göran,

“Hey, this is fun, discussing and arguing with you. I hope you feel that way too.”

Hey it is better than fun, I do not feel like we are arguing, I feel you seen something I did not, I also feel we are just debating a point so that we both learn, or at least here I am learning.

I was more focused on the copper salt, I did not even think that much about the Tin salt that much of being an oxide or nitrate of tin, I was not as concerned whether it would form nitric acid as I was of converting it to a sulfate and to remove it from the gold.

It is not arguing it is learning and sharing Ideas and what we are learning.

I see now, what you are saying, (this man slaps palm of hand up against his thick hard scull).

I was thinking the tin salt (or gelatin powder of metastannic acid) being formed from a metal of tin in nitric acid formed a tin nitrate salt, not an acidic oxide or tri-oxide of tin or an oxidized salt of tin as it has, I did not think enough about the reaction of tin in nitric acid, to see the tin is only oxidized by the strong oxidizing action of the nitric acid, probably breaking down to an oxidized tin metal just floating around in acid, being a passivated oxide of tin that would NOT form a nitrate but would just jelly.


I guess I really did not look closely enough at the formula H2SnO3 to see it did not contain the nitrate anion.

Now that I see your point (a very good point I had missed).With that in mind let me add more to this discussion of tin in nitric acid.
________________________________________________________________________
Concentrated nitric acid will break down tin to an oxide of tin powder insoluble in the acid as metastannic acid, evolving nitrogen dioxide gas: the tin does not really dissolves but stays as an oxide powder in solution forming a gelatinous substance hard to filter.

Sn + 4HNO3 --> H2SnO3 + NO2(g) + H2O

But in dilute cold nitric acid we actually form the nitrate salt of tin Sn(NO3)2 (tin nitrate salt) when we slowly dissolve the tin.
(this may mix with some meta stannic acid of this I am unsure):

In this reaction of cold dilute nitric acid reacting on tin the NOx gas does not escape, and thus forms ammonium nitrate and stannous nitrates, in this reaction tin is given 2 positive charges, and a part of the nitrogen from the nitric acid is reduced forming a positive valence of five (toward oxygen) to a negative valance of three (toward hydrogen), therefore losing eight charges, so one molecule of nitric acid oxidizes four atoms of tin, eight more molecules of nitric acid form stannous nitrate, and one form ammonium nitrate.

Reaction of tin in cold dilute HNO3 slowly forms tin nitrate salt Sn(NO3)2 and ammonium nitrate salt NH4NO3 in solution:

4Sn + 10HNO3 --> 4Sn(NO3)2 + NH4NO3 + H2O


I am unsure if this is a mute point as we concentrate the dilute solution, and may just form metastannic anyway. With concentration or drying of the tin salts, as you stated the tin and its salts is a very complicated science.

Göran, I do enjoy these discussions and like to (argue) discuss the science with you I seem to learn a lot in our discussions.

Thanks for showing me the error of my ways of my thinking (thinking has always got me into trouble) :lol:
 
srlaulis said:
This thread makes my head hurt. So much to learn :shock:
Yeah, but it's a pleasurable pain. It's called knowledge. There is so much to learn on this forum, and I try my best to read all the threads I can, especially for the task that I'm working on.

Kevin
 
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