812-22-002-30-006101--- CONN SPRING PISTON 2POS SMD--75 000 pcs
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Estimate surface area of part in sq.cm, double by 0.5 /10000 cm double by gold density in g/cub.cm, this is for one part
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You do know how to calculate area and then volume don't you?
It is plain calculator work.
Since there are no picture I have no Idea on the shape.
Length times Width in cm will give the area.
Then area times thickness will give the volume.
Thickness is 0.51micro meter which is 0.00005100000 cm
Then this volume times two, since there are 2 contacts.
In the end, times 1000 since you have 1000 of them.
Guesstimating here:
0.25 cm* (0.02* 0.02)* 2cm Which gives 0.0008* 0.25 cm2= 0.0002cm
So each is 0.0002cm3
This means each item is 0.0004cm3
So in total you have 0.0004cm3 times 1000, which is 0.4 cm3 of Gold
Theoretically you have 0.4 times 19.3 = 7.72 grams of gold at todays value of 61.5 ish USD
Total of 475 ish USD minus losses and other inconsistencies.
No warranties this is correct.
Edit:
Corrected calculation, forgot parts of the item.
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macfixer01
Well-known member
Those are some kind of goofy short little pogo pins apparently? That part number in the title is listed on the Digi-Key website but for some reason the pictures I saved from their catalog page weren’t recognized here. Similarly the data sheet PDF link was also goofy, and even if I attached the actual PDF file here it was asking me to download it instead of just displaying it. Oh well, it’s only 2 pages so I just did screenshots and will attach those here.
Attachments
Guesstimate per 1000
If you do not know how to calculate, this might not be the hobby for you.
What is your plan for these?
macfixer01
Well-known member
That number sounds insane, $475 so approximately 1/4 Toz of gold from 1000 pins that only have 20 microinches of plating? It looks like you’re figuring that using the volume of the pins, not the surface area? They aren’t solid gold.
As I said I did just a rough guesstimate and ended up with 7 ish grams per 1000.
I might have missed a decimal point somewhere.
Edit to add:
Aah I saw it now, calculated with area only so it has to be multiplied with thickness as well.
This means one ends up with 0.008 ish grams per 1000 items
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I believe it is an exceptional yield if you could manage 0.008g/1000 pins , that would mean that 75000 pins yield 600g of gold.... that amount of gold for 475 USD is a great opportunity.... I have left out the part of dealing with Beryllium from springs.
All in all i will try to calculate as well just to see what would yield 1 pin for gold.
Pete
The 475 was based on wrong calculations.
Oh I see now, i have misinterpreted the situation and calculation...after re-reading the whole post...my bad...still i will make a calculation just for the fun of it...
