Check my Chemistry/Math

[chawimac]

I have a newbie question and hope someone can check my math/chemistry. This is just very confusing to me.

I have a solution that is:

164,437.50 PPM
1.5955 Specific Gravity
49.0072 Molar Mass

Q1. If I have 1498 ml of water and add 1kg of solids in order to make a pulp that is 40% and I add 1.5 grams of a chemical, does the 1.5 grams represent 0.6% or 1% of the whole? My guess was 1% but am confused.

Q2. If I have 1498 ml of water and add 1kg of solids, and am looking to have the above solution represent 600 ppm (or 1,000ppm as per Q1 above) concentration in my solution. In my math I get that I am supposed to add 9.12ml of the 164,437.50 ppm solution. Correct? I suppose I would have to add less water than the 1498 ml if indeed I need 9 ml of solution.

Q3. As per the 164,437.50 ppm solution I get that it is 3.35537431 moles per liter and 0.1644 gr per ml, correct?

Q4. As my reagents get consumed, and my solution changes and say my PPM drops to 300 ppm from 600 (or 1,000ppm as per Q1 above), how do I calculate how much solution to add to increase my ppm back to 600 (or 1,000ppm as per Q1 above)?

Just to clarify, this is relating to chemical concentrations for a solution used in ore leaching. Hope am not posting in the wrong place.

 

[goldsilverpro]

I have a newbie question and hope someone can check my math/chemistry. This is just very confusing to me.

I have a solution that is:

164,437.50 PPM
1.5955 Specific Gravity
49.0072 Molar Mass

Q1. If I have 1498 ml of water and add 1kg of solids in order to make a pulp that is 40% and I add 1.5 grams of a chemical, does the 1.5 grams represent 0.6% or 1% of the whole? My guess was 1% but am confused.

Q2. If I have 1498 ml of water and add 1kg of solids, and am looking to have the above solution represent 600 ppm (or 1,000ppm as per Q1 above) concentration in my solution. In my math I get that I am supposed to add 9.12ml of the 164,437.50 ppm solution. Correct? I suppose I would have to add less water than the 1498 ml if indeed I need 9 ml of solution.

Q3. As per the 164,437.50 ppm solution I get that it is 3.35537431 moles per liter and 0.1644 gr per ml, correct?

Q4. As my reagents get consumed, and my solution changes and say my PPM drops to 300 ppm from 600 (or 1,000ppm as per Q1 above), how do I calculate how much solution to add to increase my ppm back to 600 (or 1,000ppm as per Q1 above)?

Just to clarify, this is relating to chemical concentrations for a solution used in ore leaching. Hope am not posting in the wrong place.

If I have misinterpreted the questions, let me know.

Q1. If I read this right, the total weight is 1498g H2O + 1000g solids = 2498g pulp. The 1.5g addition would represent 1.5/2498 = .0006 = .06% of the total weight of the pulp.
Q2. I also get 9.12ml
Q3. Correct. 164.4/49 = 3.355M and 164.4/1000 = .164g/ml
Q4. Here again, if I read this right, it would be 9.12 x 300/600 = 4.56ml

It was difficult wading through these confusing questions. For example, you might consider rounding off the numbers next time. If you can make up a liter of solution that contains exactly 164.43750g of a dissolved chemical, I will eat my hat.

 

[chawimac]

Many thanks for your help GSP!