user 72646
Well-known member
- Joined
- Sep 20, 2023
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- 152
Hi
I have dropped a gold solution with Aluminium, then filtered powders.
After filtering I the added another piece of aluminium to solution, and had another reaction and precipitation. I then filtered powders and added another piece of aluminium to solution and got another reaction, and again a powder precipitate.
So when will the reactions stop?
If the First drop recovered all metals below aluminium, then what happens on the next reaction? I assume that the First reaction recovered metals, so does the second and third reaction drop specific metals below aluminium, even though the First drop has already done this?
First Recover will be for example Au, Ag, Cu, Fe, Pt, Pd and everything below..Aluminium
Second Recovery.....?
Third recovery..........? and so on....
As aluminium goes into solution and weakens the HCL (i assume)
Is the metal which is recovered determined by acidity levels or the new chloride which has formed after initial drop?
That is, First recovery....strong acidity (metal recovered eg. au ag pt pd fe, cu)
Second weakened solution Alcl (i believe) an aluminium chloride precipitates what and why?
Again the third instance would be an AlCl+? which like the First precipitated a powder?
Note the solution has had 3 instances of aluminium recovery and still precipitates.....'something'?
Would the aluminium ions exchange with themselves, and just repeat reaction?
So far my variables/questions
Strength of solution, does this determine anything? (in terms of what comes down)
What the solution becomes after First recovery with aluminium would it be an (AlCl)+Sn?+Zn?+Fe?
Does the solution continue exchanging ions and would this impact what metals that are subsequently dropped out of solution?
How would I calculate on reactivity table?
Hope this makes sense
MM
I have dropped a gold solution with Aluminium, then filtered powders.
After filtering I the added another piece of aluminium to solution, and had another reaction and precipitation. I then filtered powders and added another piece of aluminium to solution and got another reaction, and again a powder precipitate.
So when will the reactions stop?
If the First drop recovered all metals below aluminium, then what happens on the next reaction? I assume that the First reaction recovered metals, so does the second and third reaction drop specific metals below aluminium, even though the First drop has already done this?
First Recover will be for example Au, Ag, Cu, Fe, Pt, Pd and everything below..Aluminium
Second Recovery.....?
Third recovery..........? and so on....
As aluminium goes into solution and weakens the HCL (i assume)
Is the metal which is recovered determined by acidity levels or the new chloride which has formed after initial drop?
That is, First recovery....strong acidity (metal recovered eg. au ag pt pd fe, cu)
Second weakened solution Alcl (i believe) an aluminium chloride precipitates what and why?
Again the third instance would be an AlCl+? which like the First precipitated a powder?
Note the solution has had 3 instances of aluminium recovery and still precipitates.....'something'?
Would the aluminium ions exchange with themselves, and just repeat reaction?
So far my variables/questions
Strength of solution, does this determine anything? (in terms of what comes down)
What the solution becomes after First recovery with aluminium would it be an (AlCl)+Sn?+Zn?+Fe?
Does the solution continue exchanging ions and would this impact what metals that are subsequently dropped out of solution?
How would I calculate on reactivity table?
Hope this makes sense
MM