I was wondering as I keep reading conflicting information.
Most here seem to describe equations that are really base formulas without the ion aspect.
My understanding is that for the AP process (which I agree with some here should be called the Copper Chloride process) the CuCl2 is doing the work and being very soluble in water. In water however it becomes Cu+2 and 2 Cl- ions. Being highly soluble (757g/l @25c) and the [stt]Cl- ions are what does the work attacking the metallic copper. (CuCl also does some work but due to it's low solubility it cannot be as important in the process directly.)[/stt] Edit: Wrong. The correct reaction is the Cu+2 is what is attacking the solid state copper. It creates two Cu+ ions or Cu(s) + CuCl2 makes 2CuCl.
This attack causes it to become CuCl (not directly CuCl2 which is very important!) which is not broken easily up into ions by water and just sits on the surface of the metallic copper. HCl helps here as it can dissolve it and addition of oxygen can convert CuCl into CuCl2 through the equation CuCl + O2 + HCl => CuCl2 + H2O consuming HCl in the process.
CuCl2 is Cu+2 and 2 Cl- ions and the cycle continues.
But there appears to be some fun stuff.
The colors! CuCl2 when dissolved in water changes color based on the amount of Cl- ions!
Greenish-yellow: high concentration of Cl- which also means high potential for reducing more copper.
Just greenish: middle levels of Cl-.
Blue: Very low in Cl-.
This brings me to the reason I started this topic. All my digging into this lead me to a fun tidbit about complexes. CuCl when dissolved with HCl can form complexes with CO (carbon monoxide) to [CuCl(CO)]2 and that is colorless! This may have been seen by members of the forum when they claim their solutions became colorless, not just pale blue.
Any thoughts on this? Any errors?
Most here seem to describe equations that are really base formulas without the ion aspect.
My understanding is that for the AP process (which I agree with some here should be called the Copper Chloride process) the CuCl2 is doing the work and being very soluble in water. In water however it becomes Cu+2 and 2 Cl- ions. Being highly soluble (757g/l @25c) and the [stt]Cl- ions are what does the work attacking the metallic copper. (CuCl also does some work but due to it's low solubility it cannot be as important in the process directly.)[/stt] Edit: Wrong. The correct reaction is the Cu+2 is what is attacking the solid state copper. It creates two Cu+ ions or Cu(s) + CuCl2 makes 2CuCl.
This attack causes it to become CuCl (not directly CuCl2 which is very important!) which is not broken easily up into ions by water and just sits on the surface of the metallic copper. HCl helps here as it can dissolve it and addition of oxygen can convert CuCl into CuCl2 through the equation CuCl + O2 + HCl => CuCl2 + H2O consuming HCl in the process.
CuCl2 is Cu+2 and 2 Cl- ions and the cycle continues.
But there appears to be some fun stuff.
The colors! CuCl2 when dissolved in water changes color based on the amount of Cl- ions!
Greenish-yellow: high concentration of Cl- which also means high potential for reducing more copper.
Just greenish: middle levels of Cl-.
Blue: Very low in Cl-.
This brings me to the reason I started this topic. All my digging into this lead me to a fun tidbit about complexes. CuCl when dissolved with HCl can form complexes with CO (carbon monoxide) to [CuCl(CO)]2 and that is colorless! This may have been seen by members of the forum when they claim their solutions became colorless, not just pale blue.
Any thoughts on this? Any errors?