Alentia
Well-known member
While it is pain trying to work on kovar pins with only HCL due to too many metals involved, specifically Nickel plate. I am to try and publish results attacking the pins with H2SO4 and HNO3 combo.
I wonder if anyone has already tried this method.
On another thought and I am thinking on experimenting using all 3 acids to obtain clean gold at the bottom during whole reaction, while everything else should be dissolved. The logic behind this theory:
Fe + 2HCl = FeCl2
Fe + H2SO4 = FeSO4 + H2
FeCl2 + H2SO4 = FeSO4 (will drop gold) + HCl (will be re-engaged into reaction)
Au + HCl + HNO3 = HAuCl4 + NO + H2O
2 HAuCl4(s) → Au2Cl6(s) + 2 HCl(g)
AuCl3 + 3 FeSO4 = Au + 3 FeCl + 3 SO2 + 3 O
Iron being represented in Kovar at 50% content should serve as catalyst for all of the reactions to occur. Wonder if anyone tried it already.
I wonder if anyone has already tried this method.
On another thought and I am thinking on experimenting using all 3 acids to obtain clean gold at the bottom during whole reaction, while everything else should be dissolved. The logic behind this theory:
Fe + 2HCl = FeCl2
Fe + H2SO4 = FeSO4 + H2
FeCl2 + H2SO4 = FeSO4 (will drop gold) + HCl (will be re-engaged into reaction)
Au + HCl + HNO3 = HAuCl4 + NO + H2O
2 HAuCl4(s) → Au2Cl6(s) + 2 HCl(g)
AuCl3 + 3 FeSO4 = Au + 3 FeCl + 3 SO2 + 3 O
Iron being represented in Kovar at 50% content should serve as catalyst for all of the reactions to occur. Wonder if anyone tried it already.