bemate
Well-known member
- Joined
- Sep 23, 2016
- Messages
- 72
I currently have my big batch of pins marinating in CuCl (AP). The solution is doing its job, albeit slowly, and that is as expected. The foils are coming off and the pins are going into solution. So far so good.
The question is: what to do when the solution gets saturated with copper? Judging from pH and amount of copper dissolved, there is plenty of free acid available to continue the etching, but the Cu saturation stops the process. The miser in me does not care for wasting perfectly good acid just because it can't hold its Copper. And additionally, the more acid I can deplete on solubilizing Copper, the less I need to neutralize when treating it afterwards.
If I consider this as an equilibrium, where CuCl2 + Cu + H+ --> 2 CuCl +O2 + HCl- --> 2CuCl2 + H2O (Not balanced), then obviously the reaction stops when the liquid is unable to dissolve more CuCl2, it creates a negative feedback into the circular reaction where the formation of CuCl2 from CuCl stops, and we reach a situation where the solution is saturated with both ions (Cu1+ and Cu2+).
This saturation happens regardless of the concentration of H+ (residual acid), and so the reaction stops before acid is depleted. To me, the easiest and most obvious solution is to add more water to the reaction, lowering the concentration of all parts, which is what I am currently trying. I would guess it is possible to regenerate the AP into metallic Cu and acid through some kind of electrolysis as well, but that is not my point. I want to use the acid to do its job all the way. The question is; how far can it be diluted before the acid strength gets too low? Is there a critical threshold I need to consider?
The question is: what to do when the solution gets saturated with copper? Judging from pH and amount of copper dissolved, there is plenty of free acid available to continue the etching, but the Cu saturation stops the process. The miser in me does not care for wasting perfectly good acid just because it can't hold its Copper. And additionally, the more acid I can deplete on solubilizing Copper, the less I need to neutralize when treating it afterwards.
If I consider this as an equilibrium, where CuCl2 + Cu + H+ --> 2 CuCl +O2 + HCl- --> 2CuCl2 + H2O (Not balanced), then obviously the reaction stops when the liquid is unable to dissolve more CuCl2, it creates a negative feedback into the circular reaction where the formation of CuCl2 from CuCl stops, and we reach a situation where the solution is saturated with both ions (Cu1+ and Cu2+).
This saturation happens regardless of the concentration of H+ (residual acid), and so the reaction stops before acid is depleted. To me, the easiest and most obvious solution is to add more water to the reaction, lowering the concentration of all parts, which is what I am currently trying. I would guess it is possible to regenerate the AP into metallic Cu and acid through some kind of electrolysis as well, but that is not my point. I want to use the acid to do its job all the way. The question is; how far can it be diluted before the acid strength gets too low? Is there a critical threshold I need to consider?