Hi folks,
My chemistry background is only like a couple of classes taken in high school, and those were the science-related classes in which I got the worst grades in, primarily because I couldn't balance the chemical equations.
I've been working on processing some e-waste for the first time. It's not possible to get nitric acid here without government scrutiny and monitoring my family and my for the rest of my life, so I'm going with the CuCl2 (Acid Peroxide) method. I've been successful in recovering gold foils, but I'd like a deeper understanding of what's going on and attempt some stoichiometry for the amount of HCl needed.
The reaction equations I have for dissolving copper are the following, with notes.
[1] 4 Cu + O2 -> 2 Cu2O (Cuprous Oxide). This oxygen can come from dissolution at liquid-air interface, an air bubbler, or hydrogen peroxide.
[2] 4 HCl + Cu2O -> 2 CuCl2 + H2O. This HCl is of course the thing we add.
[3] CuCl2 + Cu -> 2 CuCl. Cupric Chloride goes to work on solid copper metal to form Cuprous Chloride. This is happening along with [1].
[4] 4 HCl + 4 CuCl + O2 -> 4 CuCl2 + 2 H2O. This is the regeneration reaction.
Based on reactions [2] and [4], we need 2 and 1 molecules of HCl to process each atom of copper metal, respectively. Based on standard atomic weights, the weight ratio of a HCl molecule to a copper atom is (H(1.008)+Cl(35.45)) / Cu(63.546) = 0.5737, meaning theoretically that to dissolve a given amount of copper, exactly 57.37% of its weight in pure HCl molecules is needed.
Suppose I have 20% HCl (usually this is concentration by weight, right?), and have 100g of non-magnetic pins to dissolve. Let's assume that the 100g is all copper. The HCl acid density at 20% concentration is 1.098g/mL (from Wikipedia).
100g x 57.37% = 57.37g of HCl molecules needed to dissolve the 100g of copper.
57.37g / 20% = 286.86g of the aqueous HCl (hydrochloric acid now, no longer just gas molecules) needed to dissolve the copper.
Weight of the acid divided by density = 286.86g / 1.098g/mL = 261.26mL of 20% HCl needed to dissolve 100g of copper.
In practice though, this isn't even close to being enough. Why? I know I made some mistake and/or made insufficient or erroneous assumptions (eg. incorrect reaction formulas, not enough reactions, etc.). I'd like to be able to get a better estimate for how much HCl I would need. Call it a compulsion, but this is just for understanding... In real-life, these calculations would be estimates to give me a starting point.
It's sort of like the discussion in this thread. The theorists come up with new things that the hands-on folks use to apply to existing processes or create new ones, while the hands-on folks discover what works and what doesn't from their hands-on experience that the theorists use to improve their understanding and perhaps generate new ideas; I think it's a benign, generative cycle and is how progress is made.
Thanks a lot for any help or insights!
EDITED to correct [3] [stt]2 [/stt]CuCl2 + Cu -> 2 CuCl
My chemistry background is only like a couple of classes taken in high school, and those were the science-related classes in which I got the worst grades in, primarily because I couldn't balance the chemical equations.
I've been working on processing some e-waste for the first time. It's not possible to get nitric acid here without government scrutiny and monitoring my family and my for the rest of my life, so I'm going with the CuCl2 (Acid Peroxide) method. I've been successful in recovering gold foils, but I'd like a deeper understanding of what's going on and attempt some stoichiometry for the amount of HCl needed.
The reaction equations I have for dissolving copper are the following, with notes.
[1] 4 Cu + O2 -> 2 Cu2O (Cuprous Oxide). This oxygen can come from dissolution at liquid-air interface, an air bubbler, or hydrogen peroxide.
[2] 4 HCl + Cu2O -> 2 CuCl2 + H2O. This HCl is of course the thing we add.
[3] CuCl2 + Cu -> 2 CuCl. Cupric Chloride goes to work on solid copper metal to form Cuprous Chloride. This is happening along with [1].
[4] 4 HCl + 4 CuCl + O2 -> 4 CuCl2 + 2 H2O. This is the regeneration reaction.
Based on reactions [2] and [4], we need 2 and 1 molecules of HCl to process each atom of copper metal, respectively. Based on standard atomic weights, the weight ratio of a HCl molecule to a copper atom is (H(1.008)+Cl(35.45)) / Cu(63.546) = 0.5737, meaning theoretically that to dissolve a given amount of copper, exactly 57.37% of its weight in pure HCl molecules is needed.
Suppose I have 20% HCl (usually this is concentration by weight, right?), and have 100g of non-magnetic pins to dissolve. Let's assume that the 100g is all copper. The HCl acid density at 20% concentration is 1.098g/mL (from Wikipedia).
100g x 57.37% = 57.37g of HCl molecules needed to dissolve the 100g of copper.
57.37g / 20% = 286.86g of the aqueous HCl (hydrochloric acid now, no longer just gas molecules) needed to dissolve the copper.
Weight of the acid divided by density = 286.86g / 1.098g/mL = 261.26mL of 20% HCl needed to dissolve 100g of copper.
In practice though, this isn't even close to being enough. Why? I know I made some mistake and/or made insufficient or erroneous assumptions (eg. incorrect reaction formulas, not enough reactions, etc.). I'd like to be able to get a better estimate for how much HCl I would need. Call it a compulsion, but this is just for understanding... In real-life, these calculations would be estimates to give me a starting point.
It's sort of like the discussion in this thread. The theorists come up with new things that the hands-on folks use to apply to existing processes or create new ones, while the hands-on folks discover what works and what doesn't from their hands-on experience that the theorists use to improve their understanding and perhaps generate new ideas; I think it's a benign, generative cycle and is how progress is made.
Thanks a lot for any help or insights!
EDITED to correct [3] [stt]2 [/stt]CuCl2 + Cu -> 2 CuCl