GSP,goldsilverpro said:Use this formula to calculate the value per square inch of plated area. 10 to 25 micro inches would be .000010" to .000025" in the formula. This figures from $0.14 to $0.35 per square inch. Do the surface area calculations. From this, you should be able to make your own decision. I'm also giving a formula for silver.
For Gold: (plating thickness in inches) x 10.18 x spot price = $ value/square inch
For silver: (plating thickness in inches) x 5.53 x spot price = $ value/square inch
Thanks.goldsilverpro said:10.18 is the number of tr.oz. of pure gold in a cubic in. For silver it is 5.53 tr.oz./cu.in.
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goldsilverpro said:Use this formula to calculate the value per square inch of plated area. 10 to 25 micro inches would be .000010" to .000025" in the formula. This figures from $0.14 to $0.35 per square inch. Do the surface area calculations. From this, you should be able to make your own decision. I'm also giving a formula for silver.
For Gold: (plating thickness in inches) x 10.18 x spot price = $ value/square inch
For silver: (plating thickness in inches) x 5.53 x spot price = $ value/square inch
butcher said:speaking of number's, was reading this morning and something dawned on me.
I always thought the mole in chemistry was so small, seemed so small to me.
when I used the mole to calculate the amount of a chemical we need in the formula.
but then when you think that:
1 gram of gold = 0.005077 mole
or that:
1 mole of gold = 196.96654 grams :!: :!:
that little mole does not seem so small.
P3M said:Hey Chris
Hope all is well, 2 things
Do you have any equipment for refining / assay available for sale? Not looking for anything specific, just looking for possible deal.
2nd thing: Do you have a rough average yeild on costume gold jewellery ? ppm or g/t type analysis numbers ?
10wt_Percent said:if you have a quantity of identical (identically-plated) parts one could consider weighing a sample of say ten such items and then stripping the plating (off) and re-weighing the stripped (and dried) sample-set. The difference in weight -- divided by the sample size i.e. "normalizing" the data -- will give you (will yield) the weight (of plating) per unit article.
Sounds about right?
In theory, it is right. Practically, though, it would be quite difficult to get accuracy.10wt_Percent said:if you have a quantity of identical (identically-plated) parts one could consider weighing a sample of say ten such items and then stripping the plating (off) and re-weighing the stripped (and dried) sample-set. The difference in weight -- divided by the sample size i.e. "normalizing" the data -- will give you (will yield) the weight (of plating) per unit article.
Sounds about right?
necromancer said:don't use nitric on brass. makes for a messy mess :!:
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