Grelko
Well-known member
I've been working on some IC chips and was thinking about this.
I'm not exactly sure about the different size wires, so I'm going with the average.
If my math is wrong, please let me know where I made a mistake.
1Troy ounce of gold is 1.61 cubic centimeters.
The information has been updated later on in the thread.
The average gold bonding wire is 12.5 micrometers "Um" by 2 millimeters "mm".
At 2 mm, you need 8.05 wires to get 1.61 Cm.
1.61 cm = 16,100 Um
16,100 Um / 12.5 = 1,288 wires
So, if you take 1,288 x 1,288 = 1.61 Cm by 1.61 Cm, or 1,658,944 wires.
The 1,658,944 wires would make the "square" 2 mm high. To get the 1.61 Cm "cubed", you need to multiply by 8.05.
1,658,994 x 8.05 = 13,354,499.2 bonding wires for 1 troy ounce of gold. (Sound correct?)
So, if you divide 13,354,499.2 by 31.1035, you need 429,356.799 for 1 gram.
That would mean, if I had an IC chip that has 400 bonding wires (some BGAs are 20 x 20), I would need 1,073.4 of that chip to make 1 gram of gold. "Just counting the bonding wires"
Instead, if I took the chips that only have 6 legs/wires, I would need 71,560 for 1 gram.
The wires actually do add up pretty quick, especially the ones that have legs on all 4 sides and BGAs.
Edit- spelling
I'm not exactly sure about the different size wires, so I'm going with the average.
If my math is wrong, please let me know where I made a mistake.
1Troy ounce of gold is 1.61 cubic centimeters.
The information has been updated later on in the thread.
The average gold bonding wire is 12.5 micrometers "Um" by 2 millimeters "mm".
At 2 mm, you need 8.05 wires to get 1.61 Cm.
1.61 cm = 16,100 Um
16,100 Um / 12.5 = 1,288 wires
So, if you take 1,288 x 1,288 = 1.61 Cm by 1.61 Cm, or 1,658,944 wires.
The 1,658,944 wires would make the "square" 2 mm high. To get the 1.61 Cm "cubed", you need to multiply by 8.05.
1,658,994 x 8.05 = 13,354,499.2 bonding wires for 1 troy ounce of gold. (Sound correct?)
So, if you divide 13,354,499.2 by 31.1035, you need 429,356.799 for 1 gram.
That would mean, if I had an IC chip that has 400 bonding wires (some BGAs are 20 x 20), I would need 1,073.4 of that chip to make 1 gram of gold. "Just counting the bonding wires"
Instead, if I took the chips that only have 6 legs/wires, I would need 71,560 for 1 gram.
The wires actually do add up pretty quick, especially the ones that have legs on all 4 sides and BGAs.
Edit- spelling