Alkind of sounds like silver chloride cottage cheese,
white powder can be several metals or a combination of metals,
Chlorides are usually Copper (I), Silver, Mercury, or lead, all insoluble as chloride salts in water or dilute acid solution,copper (I) would be soluble in slightly acidic solution, and of coarse if the more noble metals were present they can be mixed with these would be insoluble.
these chlorides can be seperated and tested.
a good test to see if you have a chloride solution would be to use silver nitrate solution, if chloride was present it would precipitate a white silver chloride, as either a creamy solution or as white cottage cheese,
say you have white powdered chlorides and you want to seperate them and test, adding a dilute say about 6M solution of HCl and water, if copper the solution will turn blue to green, in cold solution, and decantingand repeating till solution clears somewhat would leave mostly the silver, mercury or lead.
(I say mostly because I believe the crystal structure of these chlorides is hard to seperate, as I think as crystals grow they do not neccasarily grow of one metal but more valuble metals may be locked up in the crystal, and without completly dissolving and seperating them they may stay locked together, just washing the outside of the crystal or disolving the outside layer of the crystal may not ever seperate them completely, also I feel if I can see it in solution and it will precipitate it is a crystal salt made up of many atoms, and possibly different types of metal atoms unless this was the only pure metal in solution), not sure my explanation here is understandable.
now AgCl, Hg2Cl2,PbCl2, insoluble in cold dilute HCl/water solution,
but heating and the lead chloride becomes more soluble, so by boiling this solution giveng time for insolubles to settle while keeping hot but not aggitated the lead chloride will dissolve into solution, and can be seperated by decanting, now if allowed to cool they would grow crystal powders of lead chloride again, a test for lead cloride is pottasium chromate with lead will show bright yellow precipitant.
the Hg2Cl2, and AgCl white cloride powders are insoluble in this dilute solution,now if we added Ammonia (caution never let this solution dry it can form dangerous shock or temperature compound, Always remove silver by acidifying solution with HCl, to precipitate silver and making solution into ammonium chloride), ammonia will dissolve silver into solution as Ag(NH3)2, and by adding HCL will precipitate white silver chloride powder (white cottage cheese), the white Hg2Cl2 in ammonia changes to gray-black precipitant of HgNH2Cl if it was ever present to begin with.
I don't know if this will answer your question or not. but hope it helps.
white powder can be several metals or a combination of metals,
Chlorides are usually Copper (I), Silver, Mercury, or lead, all insoluble as chloride salts in water or dilute acid solution,copper (I) would be soluble in slightly acidic solution, and of coarse if the more noble metals were present they can be mixed with these would be insoluble.
these chlorides can be seperated and tested.
a good test to see if you have a chloride solution would be to use silver nitrate solution, if chloride was present it would precipitate a white silver chloride, as either a creamy solution or as white cottage cheese,
say you have white powdered chlorides and you want to seperate them and test, adding a dilute say about 6M solution of HCl and water, if copper the solution will turn blue to green, in cold solution, and decantingand repeating till solution clears somewhat would leave mostly the silver, mercury or lead.
(I say mostly because I believe the crystal structure of these chlorides is hard to seperate, as I think as crystals grow they do not neccasarily grow of one metal but more valuble metals may be locked up in the crystal, and without completly dissolving and seperating them they may stay locked together, just washing the outside of the crystal or disolving the outside layer of the crystal may not ever seperate them completely, also I feel if I can see it in solution and it will precipitate it is a crystal salt made up of many atoms, and possibly different types of metal atoms unless this was the only pure metal in solution), not sure my explanation here is understandable.
now AgCl, Hg2Cl2,PbCl2, insoluble in cold dilute HCl/water solution,
but heating and the lead chloride becomes more soluble, so by boiling this solution giveng time for insolubles to settle while keeping hot but not aggitated the lead chloride will dissolve into solution, and can be seperated by decanting, now if allowed to cool they would grow crystal powders of lead chloride again, a test for lead cloride is pottasium chromate with lead will show bright yellow precipitant.
the Hg2Cl2, and AgCl white cloride powders are insoluble in this dilute solution,now if we added Ammonia (caution never let this solution dry it can form dangerous shock or temperature compound, Always remove silver by acidifying solution with HCl, to precipitate silver and making solution into ammonium chloride), ammonia will dissolve silver into solution as Ag(NH3)2, and by adding HCL will precipitate white silver chloride powder (white cottage cheese), the white Hg2Cl2 in ammonia changes to gray-black precipitant of HgNH2Cl if it was ever present to begin with.
I don't know if this will answer your question or not. but hope it helps.
