kadriver
Well-known member
I use this formula and it always works perfectly,
It assumes that all the karat gold is in fact karat gold,
Any gold filled or gold plated that makes it in with the batch will cause big problems:
Inquart calculation
wg X kt = pg X 3 = sn - (wg - pg) = sa X .95 = as
wg = weight in grams
kt = karat of the gold divided by 24
(example:10kt divided by 24 = (10/24) = .417)
pg = pure gold
sn = silver needed
sa = silver to add
as = adjusted silver to add
Example: 13.2g of 10k gold:
13.2g X .417 = 5.5g X 3 = 16.5g - (13.2g - 5.5g) = 8.8g X .95 = 8.36g
I would add 8.36g sterling silver to 13.2g of 10k scrap gold
to get an alloy of about 28% to 30% gold and 72% to 70%
base metals and silver - the perfect alloy for nitric treatments, in my opinion.
This alloy is higher than 25% gold. It may take longer for the nitric treatments
But it guards against the gold crumbling into a powder which is very undesireable
kadriver
It assumes that all the karat gold is in fact karat gold,
Any gold filled or gold plated that makes it in with the batch will cause big problems:
Inquart calculation
wg X kt = pg X 3 = sn - (wg - pg) = sa X .95 = as
wg = weight in grams
kt = karat of the gold divided by 24
(example:10kt divided by 24 = (10/24) = .417)
pg = pure gold
sn = silver needed
sa = silver to add
as = adjusted silver to add
Example: 13.2g of 10k gold:
13.2g X .417 = 5.5g X 3 = 16.5g - (13.2g - 5.5g) = 8.8g X .95 = 8.36g
I would add 8.36g sterling silver to 13.2g of 10k scrap gold
to get an alloy of about 28% to 30% gold and 72% to 70%
base metals and silver - the perfect alloy for nitric treatments, in my opinion.
This alloy is higher than 25% gold. It may take longer for the nitric treatments
But it guards against the gold crumbling into a powder which is very undesireable
kadriver