One of these interesting threads, reaching back into the past, now almost four years. Please let me add a few comments.
December 18th, 2009 4metals wrote: "The most straight forward way to get your platinum is to drop it first before the gold. Unfortunately that requires the 3x boil down to get rid of the nitric and is time consuming. Drop the platinum with saturated ammonium chloride and you should get the best yield both in quantities dropped and purity. Redissolving the salt, refiltering and dropping it again will improve purity but for the best purity you'll need to do a bromate hydrolysis.
Working up big lots of Pd/Pt-rich dental alloy scrap led me to the conclusion, the most straight forward way, to recover Pd and Pt consists in precipitating them together, as a mixture of K
2PdCl
6 and K
2PtCl
6 salts, and only then going after the gold, remaining in solution. Applying this procedure routinely, made the tedious "denoxing" process unnecessary in my practice. The mixed, solid hexachloro-metallates(IV) can be partly redissolved by applying an appropriate reductant and thus separated into crystallized K
2PtCl
6 and into K
2PdCl
4, remaining dissolved in the mother-liquor.
December 21st, 2009 Lou wrote: "Also, the sulfite drops any Ir as its dioxide if I remember correctly. EDIT: Also forgot, sometimes it is necessary (especially after the sulfite, well known for reducing Pt (IV) to Pt (II) to sparge with chlorine gas or add extra HCl and sodium chlorate/bromate (either work, but chlorate is cheaper). This ensures that all platinum is "H2PtCl6"."
In strongly acidic solution, there is no precipitation of IrO
2, if sulfite is added. Instead Ir(IV) is reduced to Ir(III), and thus K
2IrCl
6, eventually crystallized already, redissolved slowly.
The easy reduction of Pt(IV) to Pt(II), mentioned by Lou, is a fact, well explaining the sometimes only small yields of solid hexachloroplatinate, obtained after precipitation of gold by the known, usual procedure.
September 4th, 2010 HAuCl4 wrote: "Can the platinum salt be redissolved without reducing to metal, re-digesting, etc.?"
"I know the palladium salt can be redissolved with ammonia, etc."
"Is there a suitable solvent to dissolve/re-crystallize the ammonium chloroplatinate?"
- Yes, the platinum salt can be redissolved, there exist a few practicable procedures, but these belong to the realms of the more or less secret arts of PGM-refining.
- As far as I know, there are only water and/or dilute aqueous HCl appropriate solvents, in a possible procedure, where (NH
4)
2PtCl
6 is carefully reduced with a slightly less than stoichiometric amount of hydrazinium sulfate (the process is described in "Inorganic Syntheses") and recrystallized from the filtered solution of (NH
4)
2PtCl
4 by reoxidation.
December 31st, 2013 9kuuby9 wrote: "Given that Hoke states that only about 95% of the platinum is recovered as ammonium chloro-platinate from a platinum chloride solution by the addition of saturated ammonium chloride.
It is a pain to hunt down that 5%, especially when dealing with batches of 1kg, At 80g/l (12,5l of solution or more) that would be quite a lot to acidify and reduce with Zn."
In the case of your sample I would recommend, to use an anion exchanger, quaternary ammonium-type, chloride form. Give 500 grams resin beads into the reactor, containing the remaining 5% Pt and stir the suspension constantly, until no more dissolved Pt is detectable. The platinum should then be absorbed quantitatively by the resin, and the mother liquor contain not much more, than 1 to a few milligrams Pt per liter.
Here two links to two quite recent posts concerning ion-exchange:
http://goldrefiningforum.com/phpBB3/viewtopic.php?f=86&t=19554#p198434
http://goldrefiningforum.com/phpBB3/viewtopic.php?f=86&t=19554#p198631