talalstuvs
Well-known member
- Joined
- Sep 5, 2010
- Messages
- 52
I have 68 % nitirc i want 10% of Nitric Acid what would be it's ration and calculation to add water? waiting for urs reply.
goldsilverpro said:One of those simple, but confusing, math problems. An involved equation could surely be derived for this but, instead, here is a fairly straightforward logical method (assuming I didn't get confused).
According to the chart in the link above, using a temp of 20C:
1 ml of 68% HNO3 weighs 1.4048 grams
1 ml of 10% HNO3 weighs 1.0543 grams
Therefore:
1 liter of 68% weighs 1404.8 g
1 liter of 10% weighs 1054.3 g
Therefore:
1 liter of 68% contains 1404.8 x .68 = 955.3 g of HNO3
1 liter of 10% contains 1054.3 x .10 = 105.4 g of HNO3
Therefore:
To make up 1 liter of 10%, it will take (105.4/955.3) x 1000 = 110 ml of 68% HNO3 + 890 ml of distilled water.
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