Hi Arthur,
If it is really that yellow salt, Na2Pd(SO3)2x2H2O, what you have in hand, the procedure to recover metallic Pd out of it, is even more simple. Important prerequisites are, that no halide and no nitrate may be present. Thus, the salt has to be properly washed, using not too much water, since it is somewhat soluble, and the wash-water retains it's slight yellow coloration continuously. It can be reacted directly to metallic palladium simply, by heating in an excess of aqueous sulfuric acid. The active reductant for Pd(II) to Pd(0) is sulfurous acid or it's anhydride, sulfur dioxide, obtained through protonation of the sulfite-ligands contained in the complex-salt to be reduced.
[Pd(SO3)2]2- + 4 H+ ==> Pd2+ + 2 H2SO3
Pd2+ + H2SO3 + H2O => Pd(0)-metal + H2SO4 + 2 H+
H2SO3 ==> SO2 + H2O
Reduced this way, metallic Pd is obtained as a dense, grey powder, quite different from usually black and much finer powder, formed on reduction of Pd-salts with formic acid.