kurtak
Well-known member
MGH said:- Each person's two guesses, valid according to the conditions above, will be averaged together, the second guess being weighted at two times the first.
Please excuse my ignorance but I simply do not understand this part of the contest
It's the - "being weighted at two times the first" - that I don't get :?:
In other words - I have a first guess number - now I have a number in mind based on the second guess pic which I can certainly "average" between first guess number & second guess number
In other words - the first guess number is not the winning number - the second guess number is not the winning number - & the average between the first & second guess is not the winning number
How do I come up with the (winning) number that is "weighted" at two times the first guess :?:
Kurt