From my experience, this looks like (NH3)2Cl2PdCl2, diamminedichloropalladium(ii) chloride. The appearance is described as: "(Color) Faint Yellow to Yellow and Yellow-Green"
It is sparingly soluble and precipitated with the addition of HCl to your previous solution of Pd(NH3)4Cl2, tetraamminepalladium(ii) chloride.
Depending on the series of reactions some people get a dark brown solution of (NH4)2PdCl4 ammonium tetrachloropalladate(ii), this is characteristc of tetrachloropalladic(ii) acid. Even further oxidation gives hexachloropalladic(iv) acid. With ammonium chloride it precipitates a red (NH4)2PdCl6, diammine hexachloropalladate(iv). I have not been able to get this one... possibly due to adding too much ammonium chloride very early on.
I say, seperate it from the silver chloride, there's bound to be some.. after precipitating, try dissolving in only nitric acid, then add very little hcl or salt to the clear solution. adding too much Cl- will re-disolve some silver as AgCl2- ion