bhilton
Well-known member
Hi All, I was wondering if this math makes any sense.
If 1ML of common 68% Nitric acid dissolves roughly 1gram of gold.
Then does 1ML of 58% Nitric acid dissolve roughly 0.853 grams of gold?
I used a basic ratio calculation, 68 over 1 = 58 over x, therefore x = 58/68, or ~0.853.
I recovered gold from jeweler polish buffings, doing the first gold drop 2 nights ago. Then last night did the first refine and it took nearly 9 ml of my 58% nitric to dissolve all the gold mud.
Tonight after rinsing and hcl boiling, I will melt it and find out exactly what it is.
I'm very curious if the math will work - so in my theory, I used about 8.75ml of 58% nitric, so 8.75 * 0.853 = ~7.46g of Au.
Cheers everyone!
Thanks,
Bill
If 1ML of common 68% Nitric acid dissolves roughly 1gram of gold.
Then does 1ML of 58% Nitric acid dissolve roughly 0.853 grams of gold?
I used a basic ratio calculation, 68 over 1 = 58 over x, therefore x = 58/68, or ~0.853.
I recovered gold from jeweler polish buffings, doing the first gold drop 2 nights ago. Then last night did the first refine and it took nearly 9 ml of my 58% nitric to dissolve all the gold mud.
Tonight after rinsing and hcl boiling, I will melt it and find out exactly what it is.
I'm very curious if the math will work - so in my theory, I used about 8.75ml of 58% nitric, so 8.75 * 0.853 = ~7.46g of Au.
Cheers everyone!
Thanks,
Bill