when we dissolve a metal in an acid the metal gives up electrons on the atomic level, the metal is still in this solution, when we give back these electrons the metal it will precipitate back out of solution as a metal.
lets look at gold with its place on the reactivity series (if you dont have Idea about reactivity series, do a search for it on web get a chart for your refining notes), gold is at the bottom of the series, a very unreactive metal,it will not dissolve in nitric acid, it will not dissolve in hydrochloric acid, but in a combination of the two of these acids it will dissolve, the nitric oxidize's the gold and then it will become a metal salt with the chloride from the hydrochloric acid, giving up its electrons, this is now yellow dissolved salt of gold chloride, the nitric in solution will keep it dissolved, untill it is eliminated (or used up), now to get our gold back how can we do this? well one way, we could just replace the gold from solution, look at the reactivity series, and the position of copper in the series compared to gold, copper is above gold meaning it is more reactive, so by adding copper to this acidic salt of gold in solution, the copper will start dissolving giving up its electrons to the acid and if we had excess acid it would not start precipitating the gold untill all of the unreacted acid was used up, then the copper would continue giveing up its electrons but now to the dissolved gold in solution, now since the gold gets back its electrons it will form back into a metal (brown powder) and precipitate out of solution, once all of the gold has precipitated and the solution is loaded the copper bar will not dissolve any further (nothing left to take its electrons)now with dissolved copper salts in solution, all these copper atoms are missing their electrons, a metal higher in series can replace the copper from solution, and so on.
another method to get the gold from aqua regia would be to eliminate the nitric acid ( 3 boil, Hcl additions method ) and the use a chemical to precipitate the gold, here is an equation using sodium bisulfite (notice the ITE in the name NOT ATE), this is a chemical reaction with the gold chloride, not a replacement reaction like the example above.
2HAuCl4 + 2NaHSO3 --> 2Au + 4HCl + NaSO4 + SO2
the sulfur dioxide gas after the arrow gave back the gold its missing electrons, precipitating the gold.
now to get the gold pure if other metals are involve is another story.
and with yer nose in hokes book yer on the right track good work roy. hope this helps.