distortions

[arthur kierski]

what metals in solution can distort(gives false results) with a stanous chloride test?

 

[NoIdea]

Maybe Mercuric Chloride?

http://en.wikipedia.org/wiki/Tin(II)_chloride#Uses

Deano

 

[Geo]

copper can give a false positive for gold, the stain is brown too an excess of nitric acid can cause a false positive for gold. use the search box and type "stannous false positive".

 

[Palladium]

Are we talking about a specific test for just one precious metal in solution or are we talking all precious metals? What was you testing for gold,pd,pt?

 

[arthur kierski]

palladium ;i am testing for gold ----sometimes it gives a test results with gold but the brown precipitate obtained with smb is magnetic and the gold is really a small quantity in comparison with the brown( iron?)precipitate

 

[Palladium]

http://goldrefiningforum.com/phpBB3/viewtopic.php?f=37&t=10869&p=109413&hilit=plastic+spoon#p109413

Have you tried percipatating with ferrous sulfate to see if that might make a difference?


From Harold

That's entirely possible when working with a solution that contains a serious amount of gold, but you can do a test with ferrous sulfate to eliminate the gold, then test the solution for values if there's any question about content. Here's what you do: Place a drop of your solution in a spot plate cavity, then apply a crystal of ferrous sulfate. The crystal will precipitate the gold as a very thin sheet, or fine powder, leaving behind any other values. You can then test the cavity with stannous chloride to see if there is any reaction. If you get a purple reaction, you know the gold is not yet all down. If so, start another test, and stir the tiny sample with a glass rod, exposing all of it to the ferrous sulfate. The sample will change color as the gold precipitates. It's a good idea to have a tiny amount of ferrous sulfate left, which will indicate that the gold is all down. When there is no further action or color change, apply a drop of stannous chloride. With the gold gone from the solution, you can now see if there are other values present.