chrisjames
Active member
- Joined
- May 12, 2015
- Messages
- 29
Hi guys,
I've asked a similar question in another forum but I have since refined the question in the hope of a definite answer.
I have various scraps of different karat gold, melted together would equate 18K. I live in the UK and am unable to get nitric acid.
I have a good grasp of many of the processes however am unsure if this will work and don't want a frozen reaction to then have to mess about with further steps.
My questions are as follows:
If I melt the gold together (to about 18k) can I then go straight to poor man's AR, to then dissolve and precipitate (I'm worried about possible silver content and therefore silver chloride build up)
Or
Melt the gold with copper to increase the percentage of other metals (Copper and gold over silver) and then poor man's AR to dissolve.
I assume that once the solids are dissolved I can neutralise any nitrate with urea and precipitate with SMB. Then go through the washes and another possible dissolve.
Again I am sorry if I am repeating myself however I am still not too sure what to do.
Thanks in advance,
Chris
I've asked a similar question in another forum but I have since refined the question in the hope of a definite answer.
I have various scraps of different karat gold, melted together would equate 18K. I live in the UK and am unable to get nitric acid.
I have a good grasp of many of the processes however am unsure if this will work and don't want a frozen reaction to then have to mess about with further steps.
My questions are as follows:
If I melt the gold together (to about 18k) can I then go straight to poor man's AR, to then dissolve and precipitate (I'm worried about possible silver content and therefore silver chloride build up)
Or
Melt the gold with copper to increase the percentage of other metals (Copper and gold over silver) and then poor man's AR to dissolve.
I assume that once the solids are dissolved I can neutralise any nitrate with urea and precipitate with SMB. Then go through the washes and another possible dissolve.
Again I am sorry if I am repeating myself however I am still not too sure what to do.
Thanks in advance,
Chris