Digging through posts/internet/freshman chemistry:
My non-distillation nitric acid proved too weak for my liking so I'm going to produce my next batch via distillation.
I have approximately 5 moles of Sodium Nitrate left so using the following formula.
5 NaNO3 + 2.5 H2SO4 → 5 HNO3 + 2.5 Na2SO4
Sodium Nitrate + Sulfuric Acid -> Nitric Acid + Sodium Sulphate
425.0g + 245.2g (133ml) -> 315.1g (209ml) + 355.1g
Values rounded to nearest 0.1g
Values Used
NaNO3 = 84.99467 g/mol
H2SO4 = 98.07848 g/mol Density 1.84 g/ml
Na2SO4 = 142.04214 g/mol
HNO3 = 63.01284 g/mol Density 1.51 g/ml
Basically looking for a double check of my formula and math.
TIA,
Ric
My non-distillation nitric acid proved too weak for my liking so I'm going to produce my next batch via distillation.
I have approximately 5 moles of Sodium Nitrate left so using the following formula.
5 NaNO3 + 2.5 H2SO4 → 5 HNO3 + 2.5 Na2SO4
Sodium Nitrate + Sulfuric Acid -> Nitric Acid + Sodium Sulphate
425.0g + 245.2g (133ml) -> 315.1g (209ml) + 355.1g
Values rounded to nearest 0.1g
Values Used
NaNO3 = 84.99467 g/mol
H2SO4 = 98.07848 g/mol Density 1.84 g/ml
Na2SO4 = 142.04214 g/mol
HNO3 = 63.01284 g/mol Density 1.51 g/ml
Basically looking for a double check of my formula and math.
TIA,
Ric