modtheworld44 said:
rewalston said:
Ok, I have two buckets going, I have my Stockpot with copper in it and my other bucket with iron. We know that With the copper pot it will drop any PMs that may be in solution, and we know that the iron pot will drop copper (and any minute PMs). I have been thinking (which sometimes gets me into trouble). My processes have all been cucl2 up to this point for getting foils from pins and boards. What I was wondering. Could you use the iron pot w/heat and H2O2 as an oxidizer work to remove the gold (and copper) from things like coaxial cable ends or other things that might have another metal besides copper as a base? Looking at the reactivity series, that should work, but I'm just not certain, so that's why I'm asking. I can't afford to go the normal route with a gold cell for plating. I have sulfuric acid but don't have a charger to hook up for a gold cell.
Rusty
rewalston
The underlined and colored part that I included in your post,will convert the Ferrous Chloride you'll start with from your stockpot,to Ferric Chloride.From there add heat at a boil and it will start to dissolve the metals at a much faster rate than putting it on a lower heat setting.If it starts to get thick add a little HCl to thin it out a little.Don't over dilute it with HCl the more concentrated it is the better it works.Thanks in advance.
modtheworld44
Let me see if I can explain this. To make Ferric Chloride, all you need is steel wool or iron nails, H202-3%, HCl-32%, water and heat. This is true. Put the nails or steel wool in the HCl and allow it to dissolve completely, you will have a green Ferrous chloride solution. Then add H2O2 slowly to the solution ( this will create a lot of heat) oxidizing the Ferrous Chloride turning it into Ferric Chloride a reddish brown color.
If you have a stock pot that you put your solutions in and then add Iron to drop out any metals below it, then Add H202 and heat
does not make it Ferric Chloride. You already have other salts mixed in the solution.
That is my understanding. I may be wrong but, if I am someone will correct this.
Ken