% in chemistry is always weight percent, if nothing else is mentioned.
So 50% is 50g NaOH per 50g water.
Often it is easier to work with a concentration defined in mol: 1M NaOH would be 39,997g NaOH in 1 liter solution. About 12,5M NaOH would be 50wt%.
Why is it easier? Now, if you have used 1liter 12,5M NaOH dissolving tin and each mol of tin will use 2 mol NaOH, then you will have 6,25 mol tin or 741,9375g of tin in solution at the point of complete reaction, which ofcourse never will be reached in a slow reaction. Try to calculate this with wt%, - good luck :mrgreen:
So even you don't want to use sophistcated chemical formulas, it might be worth thinking in mol and you will be able to calculate stoichiometric amounts in your head.