home brew HCl
table salt and sulfuric acid to make muratic acid
2NaCL + H2SO4 --> Na2SO4 + 2HCl
(HCl gas if no water was involved),
2 NaCl (table salt),
2 Na --- 2 x 23 g/mol = 46g/mol (sodium),
2 Cl --- 2 x 35 g/mol = 70 g/mol (clorine),
(46+70) = 116g/mol (2 table salt),
plus,
H2SO4 (sulfuric acid),
2 H --- 2 x 1 = 2g/mol (hydrogen),
S ---32g/mol (sulfur),
4 O ---4 x 16 = 64g/mol (oxygen),
(2+32+64)=98g/mol (sulfuric acid),
so 116g/mol table salt reacts with 98g/mol sulfuric acid on left side of arrow,
---------->
now for our products on the right side of arrow,
Na2SO4 (sodium sulfate),
Na2 -- 2 x 23 + 46g/mol (sodium),
S --32g/mol (sulfur),
O4 -- 4 x 16 = 64g/mol (oxygen),
(46+32+64) = 142g/mol (sodium sulfate),
plus,
2HCl (hydrogen chloride) gas if no water involved,
2H --- 2 x 1 = 2g/mol (hydrogen),
2Cl --- 2 x 35 = 70g/mol ( chlorine),
(2 + 70) = 72g/mol (2 HCl gas)
so our products on right side of arrow is 142g/mol of sodium sulfate and 72g/mol of hydrogenchloride gas if no water was added in equation,
some water would be there and how much we used can be another story, if we had alot of water the HCL (mixed like muratic acid) up to the azeotrope of the solution (I'm not sure but 20% seems familiar I may be wrong here?),HCL would be in this water solution and the sodium sulfate will be a precipitant at bottom of this, chilling may help to get most of it to settle out, for processes that the sulfate which may stay in solution this would be all you needed, but for others distilling would leave all the salt behind in reaction vessel. and running gas through water by bubbling would give you a pretty pure muratic acid (if dilute can be concentrated to azeotrope, if too concentrated will have excess HCL gas leave water solution),
Now forgive me if there are any mistakes in this as I have never had a chemistry class and could not even read when I got out of school, so my math and chemistry is not the one to learn from.and I hope I did not mess this up to bad.I'm just learning too. :lol: