spcake---
From your picture, your solution is only 1/2 cup, and yellow. Plus 1/2 cup or more of froth, about the same color.
If the whole ounce was in solution, I think it would be closer to a red color.
If the whole ounce was in metallic form in the froth, there would be so much weighty solid bulk, that I think at least a good part of it would fall to the bottom of the measuring cup.
A half cup of froth would have more air than solution, so if your ounce of gold was entirely in solution, including the froth, you would only have maybe 3/4 cup of solution---and I think it should still be a darker color, at least orange or red-orange. Maybe all the SMB and urea would account for the light color, I have never done that (among the many other mistakes I've made!) so I can't say for sure.
Maybe knowing what you should have done can put things into perspective, and help you sort this out. First, for practice, use a 1 gram bar instead of a full ounce. Put it into about 200 ml of HCl, and add a drop of nitric. Put it on heat to 150 to 160 degrees F (use a $25.00 IR "gun" thermometer). Watch the color change and bubbles (reaction) from the gold bar. When the reaction stops, add a little more nitric. Keep letting the reaction stop, and adding nitric, until you have an orange color, then take it off the heat when there are no more bubbles.
When there are no more bubbles, all the nitric will be gone. You should have a small chunk of the bar left on the bottom. (Whatever the color of the solution, stop adding nitric while there is still a small chunk of gold left, to be sure there is no more nitric in your gold solution.)
Pour this solution into three small bottles with lids. Make it so there is about 125 ml in one bottle, 50 ml in the second bottle, and 25 ml in the third. Cap and keep the 125 ml bottle as a reference. Fill the other two bottles up to 100 ml total each, with water. Use the two diluted solutions as your standard gold solutions for testing---one being weaker than the other will give you an idea of the sensitivity of your stannous chloride testing solution. You can even make another bottle of gold solution which is half the strength of the 25 ml bottle, to see how sensitive stannous is with solutions that are barely yellow. I've seen it indicate on filters which have been sprayed down with water until there is no yellow color at all, even.
Then make some stannous chloride solution for testing for gold in solution. There are several sources of material to make it with. Some people use tin solder (lead-free), some use the white powdered stannous chloride, and other methods. Then dissolve it in HCl. Some add water. Hoke lists her formula, and there are many mentions of various ways in the forum---just use the search feature at the top right of each page. Like the experts say, the most important thing is that you always make your testing solution of the same proportions, so you become accustomed to, and thus understand its indications with unknown solutions.
You said that you have some stannous solution that you bought, so you can test that with your standard gold solutions that you made. This will give you a certainty of what to expect when you test any unknown solutions.
If you are uncertain of your stannous solution, and you are uncertain of your gold solution, the only conclusions that you can possibly come to will always be uncertain when something unusual happens, like what you have now.
Just like in navigation, you absolutely must have some points of known positions. Testing solutions which you are sure about will provide those known points. Your standard gold solutions will provide certainty about your stannous solutions.
Understanding this will help you get out of your situation with your gold solution.
