samuldacamul
Member
- Joined
- Nov 10, 2010
- Messages
- 22
Again another question:
I have once again attempted the poor man's AR process. This time I removed cpu lids and put lids and cpus in the HCl, and proceeded to heat. Just before it started boiling I added the sodium nitrate. I added more when the reaction stopped. After these steps, I let the solution evaporate down to a "thick syrup" or about 1/5 of its original volume. My question is, how much HCl should I add at this point to "expel the nitric as brown vapors?" When I added it, the soltion turned from a dark color, to yellow, but I saw no brown vapors. I took a small sample of this solution to atempt an SMB drop. When I added the SMB, the solution turned brownish red, but it went back to yellow with very little precipitation, along with salts.
I don't understand how HCl would expel the nitric anyway. What would the chemical equation be?
Thank you guys for the help. Also, the solution did test positive for gold before and after the attempted drop.
I have once again attempted the poor man's AR process. This time I removed cpu lids and put lids and cpus in the HCl, and proceeded to heat. Just before it started boiling I added the sodium nitrate. I added more when the reaction stopped. After these steps, I let the solution evaporate down to a "thick syrup" or about 1/5 of its original volume. My question is, how much HCl should I add at this point to "expel the nitric as brown vapors?" When I added it, the soltion turned from a dark color, to yellow, but I saw no brown vapors. I took a small sample of this solution to atempt an SMB drop. When I added the SMB, the solution turned brownish red, but it went back to yellow with very little precipitation, along with salts.
I don't understand how HCl would expel the nitric anyway. What would the chemical equation be?
Thank you guys for the help. Also, the solution did test positive for gold before and after the attempted drop.