lysdexic
Well-known member
lazersteve said:The water soluble starting CuCl2 is dissolved into the fresh solution as it forms. As more copper is dissolved into the solution by the etch the two chlorine atoms are spread across two copper atoms becoming 2CuCl which ultimately saturates the solution as the process repeats and CuCl eventually precipitates as as solid. Adding more HCl dissolves the CuCl as it is soluble in concentrated HCl. If an oxidizer (O2, electrons, etc.) is present, the CuCl2 regenerates and the solution becomes useful again.
The overall reaction is mainly dependent upon the solubility of the active ingredient, CuCl2 and the free HCl in the solution.
1) There should be no sediment forming (insoluble CuCl, tested by adding a few drops of water: Whitish sediment when water added = saturated with CuCl).
2) There should be free HCl in the solution (to keep the CuCl dissolved).
3) There should be a source of oxygen supplied over the course of the reaction (to keep the converting the CuCl back to CuCl2).
Of course, this an overly simplified explanation of the reaction, but it does describe the key points to keeping your solution fresh and ready to consume more copper.
Steve
Thank you Steve, I can't really put anything together right at the moment, had a migraine all day. With all the ground work you've done and the willingness of yourself and the other experienced member's to help me (and all the other apprentices and journeymen) I'm (we're) learning. I need to read your pdf again and go over all these posts again before saying any more. I want to be clear with what I do understand and what I'm unsure of so I don't waste the most valuable resource here... all of you guy's time.
I also read the topic you linked to concerning the mason jar acquaintance experiment and have that tumbling around in my head too right now. Thank you again.
Doug