Varmint
Member
pgms4me:
Yes, the heat absolutely drives the O2 out, that part is understood, but I had made the assumption (hate that word ), that it had also driven out the HCl which might have contributed to the gorgeous color change.
The bad part of my thinking (I assume) is the color comparison was indicating the level of acid, when it really appears to be indicating the quantity of Cl- ions bound up in the CuCl2?
I guess my expectation was the color I had was what I could expect when I reduced the H2O content and (presumably) started to get crystals of the Dihydrate also shown at the same wiki page.
So, my plans are to understand the chemistry. Yes, I tend to get hung up on stuff like this, I'm doing this to learn (no expectations of vast income from my effort) and I'm not the type to explain to someone how I got my gold button; "well, I used this compound I know nothing about to remove base metals, copper in this case, leaving the gold substantially pure enough for easy further refinement". I want to know why H2O2 or air work well, difference being you can add too much H2O2, but not air. That sort of open-ended "rule" drives me to learn "what IS too much H2O2", and If I have enough O2 concentration through air injection to cause the gorgeous color change, why is THAT not too much?
Further, if my O2 saturation wasn't too high, does that mean I can add H2O2 until I get the same color shift, or do the two differ enough in practice that the amount of H2O2 to cause the same shift is way too much and gold will go into solution?
Its all about learning and understanding. There are probably thousands of people who couldn't care less about how it works, but could be wildly successful scrapping/refining for profit. I want to be the guy that knows the actual chemistry, and again, have no dreams of being a wildly successful PM processor.
DAS
Yes, the heat absolutely drives the O2 out, that part is understood, but I had made the assumption (hate that word ), that it had also driven out the HCl which might have contributed to the gorgeous color change.
The bad part of my thinking (I assume) is the color comparison was indicating the level of acid, when it really appears to be indicating the quantity of Cl- ions bound up in the CuCl2?
I guess my expectation was the color I had was what I could expect when I reduced the H2O content and (presumably) started to get crystals of the Dihydrate also shown at the same wiki page.
So, my plans are to understand the chemistry. Yes, I tend to get hung up on stuff like this, I'm doing this to learn (no expectations of vast income from my effort) and I'm not the type to explain to someone how I got my gold button; "well, I used this compound I know nothing about to remove base metals, copper in this case, leaving the gold substantially pure enough for easy further refinement". I want to know why H2O2 or air work well, difference being you can add too much H2O2, but not air. That sort of open-ended "rule" drives me to learn "what IS too much H2O2", and If I have enough O2 concentration through air injection to cause the gorgeous color change, why is THAT not too much?
Further, if my O2 saturation wasn't too high, does that mean I can add H2O2 until I get the same color shift, or do the two differ enough in practice that the amount of H2O2 to cause the same shift is way too much and gold will go into solution?
Its all about learning and understanding. There are probably thousands of people who couldn't care less about how it works, but could be wildly successful scrapping/refining for profit. I want to be the guy that knows the actual chemistry, and again, have no dreams of being a wildly successful PM processor.
DAS